Question
Answer
$$\dfrac{\sqrt{49}}{\sqrt{81}}=\dfrac{7}{9}$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}\frac{\sqrt{49}}{\sqrt{81}}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{\sqrt{49}}{\sqrt{81}}\frac{\sqrt{81}}{\sqrt{81}} \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}\frac{63}{81} \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle3}{\textcircled {3}} } }}} \frac{ 63 : \color{orangered}{ 9 } }{ 81 : \color{orangered}{ 9 }} \xlongequal{ } \\[1 em] & \xlongequal{ }\frac{7}{9}\end{aligned} $$ | |
| ① | Multiply the numerator and denominator by the conjugate of the denominator . $$\color{blue}{ \sqrt{81}} $$. |
| ② | Multiply in a numerator. $$ \color{blue}{ \sqrt{49} } \cdot \sqrt{81} = 63 $$ Simplify denominator. $$ \color{blue}{ \sqrt{81} } \cdot \sqrt{81} = 81 $$ |
| ③ | Divide both the top and bottom numbers by $ \color{orangered}{ 9 } $. |
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