Question
Answer
$$\sqrt{48}+4\sqrt{6}-\sqrt{16}-4\sqrt{2}=4\sqrt{3}+4\sqrt{6}-4-4\sqrt{2}$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}\sqrt{48}+4\sqrt{6}-\sqrt{16}-4\sqrt{2}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}4\sqrt{3}+4\sqrt{6}-4-4\sqrt{2}\end{aligned} $$ | |
| ① | $$ \sqrt{48} =
\sqrt{ 4 ^2 \cdot 3 } =
\sqrt{ 4 ^2 } \, \sqrt{ 3 } =
4 \sqrt{ 3 }$$ |
| ② | $$ - \sqrt{16} = -1 \cdot 4 = -4 $$ |
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