Question
Answer
$$\sqrt{48}\cdot(6+1)=28\sqrt{3}$$
Explanation
| $$ \begin{aligned}\sqrt{48}\cdot(6+1)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}4\sqrt{3}\cdot7 \xlongequal{ } \\[1 em] & \xlongequal{ }4\cdot7\sqrt{3} \xlongequal{ } \\[1 em] & \xlongequal{ }28\sqrt{3}\end{aligned} $$ | |
| ① | $$ \sqrt{48} =
\sqrt{ 4 ^2 \cdot 3 } =
\sqrt{ 4 ^2 } \, \sqrt{ 3 } =
4 \sqrt{ 3 }$$Combine like terms |
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