Question
Answer
$$\sqrt{4}\cdot(\sqrt{8}+3)=4\sqrt{2}+6$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}\sqrt{4}\cdot(\sqrt{8}+3)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}2(2\sqrt{2}+3) \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle3}{\textcircled {3}} } }}}4\sqrt{2}+6\end{aligned} $$ | |
| ① | $$ \sqrt{4} = 2 $$ |
| ② | $$ \sqrt{8} =
\sqrt{ 2 ^2 \cdot 2 } =
\sqrt{ 2 ^2 } \, \sqrt{ 2 } =
2 \sqrt{ 2 }$$ |
| ③ | $$ \color{blue}{ 2 } \cdot \left( 2 \sqrt{2} + 3\right) = \color{blue}{2} \cdot 2 \sqrt{2}+\color{blue}{2} \cdot3 = \\ = 4 \sqrt{2} + 6 $$ |
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