Question
Answer
$$\sqrt{3}\cdot\sqrt{2}\sqrt{6}-\sqrt{3}-\sqrt{4}\cdot\sqrt{3}\sqrt{6}-\sqrt{2}+\sqrt{2}\cdot\sqrt{3}\sqrt{6}+2=14-\sqrt{3}-7\sqrt{2}$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}\sqrt{3}\cdot\sqrt{2}\sqrt{6}-\sqrt{3}-\sqrt{4}\cdot\sqrt{3}\sqrt{6}-\sqrt{2}+\sqrt{2}\cdot\sqrt{3}\sqrt{6}+2& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} \htmlClass{explanationCircle explanationCircle3}{\textcircled {3}} } }}}6-\sqrt{3}-6\sqrt{2}-\sqrt{2}+6+2 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle4}{\textcircled {4}} } }}}14-\sqrt{3}-7\sqrt{2}\end{aligned} $$ | |
| ① | $$ \sqrt{36} = 6 $$ |
| ② | $$ - \sqrt{72} =
- \sqrt{ 6 ^2 \cdot 2 } =
- \sqrt{ 6 ^2 } \, \sqrt{ 2 } =
- 6 \sqrt{ 2 }$$ |
| ③ | $$ \sqrt{36} = 6 $$ |
| ④ | Combine like terms |
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