Question
Answer
$$\sqrt{35}\cdot(8-\sqrt{7})=8\sqrt{35}-7\sqrt{5}$$
Explanation
| $$ \begin{aligned}\sqrt{35}\cdot(8-\sqrt{7})& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}8\sqrt{35}-7\sqrt{5}\end{aligned} $$ | |
| ① | $$ \color{blue}{ \sqrt{35} } \cdot \left( 8- \sqrt{7}\right) = \color{blue}{ \sqrt{35}} \cdot8+\color{blue}{ \sqrt{35}} \cdot- \sqrt{7} = \\ = 8 \sqrt{35}- 7 \sqrt{5} $$ |
This page was created using
Simplify Radical Expression