Question
Answer
$$\sqrt{3}\cdot(\sqrt{6}+3)=3\sqrt{2}+3\sqrt{3}$$
Explanation
| $$ \begin{aligned}\sqrt{3}\cdot(\sqrt{6}+3)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}3\sqrt{2}+3\sqrt{3}\end{aligned} $$ | |
| ① | $$ \color{blue}{ \sqrt{3} } \cdot \left( \sqrt{6} + 3\right) = \color{blue}{ \sqrt{3}} \cdot \sqrt{6}+\color{blue}{ \sqrt{3}} \cdot3 = \\ = 3 \sqrt{2} + 3 \sqrt{3} $$ |
This page was created using
Simplify Radical Expression