| $$ \begin{aligned}\sqrt{3}\cdot(4+4\sqrt{3})& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}4\sqrt{3}+12\end{aligned} $$ | |
| ① | $$ \color{blue}{ \sqrt{3} } \cdot \left( 4 + 4 \sqrt{3}\right) = \color{blue}{ \sqrt{3}} \cdot4+\color{blue}{ \sqrt{3}} \cdot 4 \sqrt{3} = \\ = 4 \sqrt{3} + 12 $$ |