Question
Answer
$$\sqrt{3}\cdot(\sqrt{3}+\sqrt{2})=3+\sqrt{6}$$
Explanation
| $$ \begin{aligned}\sqrt{3}\cdot(\sqrt{3}+\sqrt{2})& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}3+\sqrt{6}\end{aligned} $$ | |
| ① | $$ \color{blue}{ \sqrt{3} } \cdot \left( \sqrt{3} + \sqrt{2}\right) = \color{blue}{ \sqrt{3}} \cdot \sqrt{3}+\color{blue}{ \sqrt{3}} \cdot \sqrt{2} = \\ = 3 + \sqrt{6} $$ |
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