Question
Answer
$$\sqrt{3}\cdot(9-\sqrt{5})=9\sqrt{3}-\sqrt{15}$$
Explanation
| $$ \begin{aligned}\sqrt{3}\cdot(9-\sqrt{5})& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}9\sqrt{3}-\sqrt{15}\end{aligned} $$ | |
| ① | $$ \color{blue}{ \sqrt{3} } \cdot \left( 9- \sqrt{5}\right) = \color{blue}{ \sqrt{3}} \cdot9+\color{blue}{ \sqrt{3}} \cdot- \sqrt{5} = \\ = 9 \sqrt{3}- \sqrt{15} $$ |
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