Question
Answer
$$\dfrac{\sqrt{27}}{\sqrt{4}}=\dfrac{3\sqrt{3}}{2}$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}\frac{\sqrt{27}}{\sqrt{4}}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{\sqrt{27}}{\sqrt{4}}\frac{\sqrt{4}}{\sqrt{4}} \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}\frac{6\sqrt{3}}{4} \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle3}{\textcircled {3}} } }}}\frac{ 6 \sqrt{ 3 } : \color{blue}{ 2 } } { 4 : \color{blue}{ 2 }} \xlongequal{ } \\[1 em] & \xlongequal{ }\frac{3\sqrt{3}}{2}\end{aligned} $$ | |
| ① | Multiply the numerator and denominator by the conjugate of the denominator . $$\color{blue}{ \sqrt{4}} $$. |
| ② | Multiply in a numerator. $$ \color{blue}{ \sqrt{27} } \cdot \sqrt{4} = 6 \sqrt{3} $$ Simplify denominator. $$ \color{blue}{ \sqrt{4} } \cdot \sqrt{4} = 4 $$ |
| ③ | Divide numerator and denominator by $ \color{blue}{ 2 } $. |
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