Question
Answer
$$\sqrt{24}+2\sqrt{96}-\sqrt{25}=10\sqrt{6}-5$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}\sqrt{24}+2\sqrt{96}-\sqrt{25}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} \htmlClass{explanationCircle explanationCircle3}{\textcircled {3}} } }}}2\sqrt{6}+8\sqrt{6}-5 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle4}{\textcircled {4}} } }}}10\sqrt{6}-5\end{aligned} $$ | |
| ① | $$ \sqrt{24} =
\sqrt{ 2 ^2 \cdot 6 } =
\sqrt{ 2 ^2 } \, \sqrt{ 6 } =
2 \sqrt{ 6 }$$ |
| ② | $$ 2 \sqrt{96} =
2 \sqrt{ 4 ^2 \cdot 6 } =
2 \sqrt{ 4 ^2 } \, \sqrt{ 6 } =
2 \cdot 4 \sqrt{ 6 } =
8 \sqrt{ 6 } $$ |
| ③ | $$ - \sqrt{25} = -1 \cdot 5 = -5 $$ |
| ④ | Combine like terms |
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