| $$ \begin{aligned}\sqrt{22}\cdot(-7-10\sqrt{5})& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}-7\sqrt{22}-10\sqrt{110}\end{aligned} $$ | |
| ① | $$ \color{blue}{ \sqrt{22} } \cdot \left( -7- 10 \sqrt{5}\right) = \color{blue}{ \sqrt{22}} \cdot-7+\color{blue}{ \sqrt{22}} \cdot- 10 \sqrt{5} = \\ = - 7 \sqrt{22}- 10 \sqrt{110} $$ |