Question
Answer
$$\sqrt{2}\cdot(\sqrt{6}-\sqrt{3})=2\sqrt{3}-\sqrt{6}$$
Explanation
| $$ \begin{aligned}\sqrt{2}\cdot(\sqrt{6}-\sqrt{3})& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}2\sqrt{3}-\sqrt{6}\end{aligned} $$ | |
| ① | $$ \color{blue}{ \sqrt{2} } \cdot \left( \sqrt{6}- \sqrt{3}\right) = \color{blue}{ \sqrt{2}} \cdot \sqrt{6}+\color{blue}{ \sqrt{2}} \cdot- \sqrt{3} = \\ = 2 \sqrt{3}- \sqrt{6} $$ |
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