Question
Answer
$$\sqrt{2}\cdot(\sqrt{10}-2\sqrt{2})=2\sqrt{5}-4$$
Explanation
| $$ \begin{aligned}\sqrt{2}\cdot(\sqrt{10}-2\sqrt{2})& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}2\sqrt{5}-4\end{aligned} $$ | |
| ① | $$ \color{blue}{ \sqrt{2} } \cdot \left( \sqrt{10}- 2 \sqrt{2}\right) = \color{blue}{ \sqrt{2}} \cdot \sqrt{10}+\color{blue}{ \sqrt{2}} \cdot- 2 \sqrt{2} = \\ = 2 \sqrt{5}-4 $$ |
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Simplify Radical Expression