Question
Answer
$$\sqrt{2}\cdot(2\sqrt{3}-4\sqrt{2})=2\sqrt{6}-8$$
Explanation
| $$ \begin{aligned}\sqrt{2}\cdot(2\sqrt{3}-4\sqrt{2})& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}2\sqrt{6}-8\end{aligned} $$ | |
| ① | $$ \color{blue}{ \sqrt{2} } \cdot \left( 2 \sqrt{3}- 4 \sqrt{2}\right) = \color{blue}{ \sqrt{2}} \cdot 2 \sqrt{3}+\color{blue}{ \sqrt{2}} \cdot- 4 \sqrt{2} = \\ = 2 \sqrt{6}-8 $$ |
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Simplify Radical Expression