Question
Answer
$$\dfrac{\sqrt{192}}{2}=4\sqrt{3}$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}\frac{\sqrt{192}}{2}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{ \sqrt{ 64 \cdot 3 } }{ 2 } \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}\frac{ \sqrt{ 64 } \cdot \sqrt{ 3 } }{ 2 } \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle3}{\textcircled {3}} } }}}\frac{8\sqrt{3}}{2} \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle4}{\textcircled {4}} } }}} \frac{ 8 \cdot \sqrt{ 3 } : \color{orangered}{ 2 }}{ 2 : \color{orangered}{ 2 }} \xlongequal{ } \\[1 em] & \xlongequal{ }\frac{4\sqrt{3}}{1} \xlongequal{ } \\[1 em] & \xlongequal{ }4\sqrt{3}\end{aligned} $$ | |
| ① | Factor out the largest perfect square of 192. ( in this example we factored out $ 64 $ ) |
| ② | Rewrite $ \sqrt{ 64 \cdot 3 } $ as the product of two radicals. |
| ③ | The square root of $ 64 $ is $ 8 $. |
| ④ | Divide numerator and denominator by $ \color{orangered}{ 2 } $. |
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