Question
Answer
$$\sqrt{14}\cdot(6-\sqrt{21})=6\sqrt{14}-7\sqrt{6}$$
Explanation
| $$ \begin{aligned}\sqrt{14}\cdot(6-\sqrt{21})& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}6\sqrt{14}-7\sqrt{6}\end{aligned} $$ | |
| ① | $$ \color{blue}{ \sqrt{14} } \cdot \left( 6- \sqrt{21}\right) = \color{blue}{ \sqrt{14}} \cdot6+\color{blue}{ \sqrt{14}} \cdot- \sqrt{21} = \\ = 6 \sqrt{14}- 7 \sqrt{6} $$ |
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