Question
Answer
$$\dfrac{\sqrt{12}}{\sqrt{3}}\cdot2=4$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}\frac{\sqrt{12}}{\sqrt{3}}\cdot2& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{6}{3}\cdot2 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}\frac{ 6 : \color{orangered}{ 3 } }{ 3 : \color{orangered}{ 3 }} \cdot 2 \xlongequal{ } \\[1 em] & \xlongequal{ }\frac{2}{1}\cdot2 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle3}{\textcircled {3}} } }}}2\cdot2 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle4}{\textcircled {4}} } }}}4\end{aligned} $$ | |
| ① | Multiply in a numerator. $$ \color{blue}{ \sqrt{12} } \cdot \sqrt{3} = 6 $$ Simplify denominator. $$ \color{blue}{ \sqrt{3} } \cdot \sqrt{3} = 3 $$ |
| ② | Divide both the top and bottom numbers by $ \color{orangered}{ 3 } $. |
| ③ | Remove 1 from denominator. |
| ④ | $ 2 \cdot 2 = 4 $ |
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