Question
Answer
$$\sqrt{10}\cdot(3-2\sqrt{6})=3\sqrt{10}-4\sqrt{15}$$
Explanation
| $$ \begin{aligned}\sqrt{10}\cdot(3-2\sqrt{6})& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}3\sqrt{10}-4\sqrt{15}\end{aligned} $$ | |
| ① | $$ \color{blue}{ \sqrt{10} } \cdot \left( 3- 2 \sqrt{6}\right) = \color{blue}{ \sqrt{10}} \cdot3+\color{blue}{ \sqrt{10}} \cdot- 2 \sqrt{6} = \\ = 3 \sqrt{10}- 4 \sqrt{15} $$ |
This page was created using
Simplify Radical Expression