Question
Answer
$$\sqrt{10}\cdot(-2\sqrt{2}-2\sqrt{6})=-4\sqrt{5}-4\sqrt{15}$$
Explanation
| $$ \begin{aligned}\sqrt{10}\cdot(-2\sqrt{2}-2\sqrt{6})& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}-4\sqrt{5}-4\sqrt{15}\end{aligned} $$ | |
| ① | $$ \color{blue}{ \sqrt{10} } \cdot \left( - 2 \sqrt{2}- 2 \sqrt{6}\right) = \color{blue}{ \sqrt{10}} \cdot- 2 \sqrt{2}+\color{blue}{ \sqrt{10}} \cdot- 2 \sqrt{6} = \\ = - 4 \sqrt{5}- 4 \sqrt{15} $$ |
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