Question
Answer
$$\sqrt{5-2}^2+(0+4)^2=\sqrt{5-2}^2+16$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}\sqrt{5-2}^2+(0+4)^2& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\sqrt{5-2}^2+4^2 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}\sqrt{5-2}^2+16\end{aligned} $$ | |
| ① | Combine like terms |
| ② | $ 4 ^ 2 = 16 $ |
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