Question
Answer
$$\sqrt{10-2^2}+8-0^2=\sqrt{10-2^2}+8$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}\sqrt{10-2^2}+8-0^2& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\sqrt{10-2^2}+8-0 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}\sqrt{10-2^2}+8\end{aligned} $$ | |
| ① | $ 0 ^ 2 = 0 $ |
| ② | Combine like terms |
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