Question
Answer
$$9\cdot\dfrac{\sqrt{6}}{3}\sqrt{6}=18$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}9 \cdot \frac{\sqrt{6}}{3}\sqrt{6}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{54}{3} \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}} \frac{ 54 : \color{orangered}{ 3 } }{ 3 : \color{orangered}{ 3 }} \xlongequal{ } \\[1 em] & \xlongequal{ }\frac{18}{1} \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle3}{\textcircled {3}} } }}}18\end{aligned} $$ | |
| ① | $$ \color{blue}{ 9 \sqrt{6} } \cdot \sqrt{6} = 54 $$$$ \color{blue}{ 3 } \cdot 1 = 3 $$ |
| ② | Divide both the top and bottom numbers by $ \color{orangered}{ 3 } $. |
| ③ | Remove 1 from denominator. |
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