Question
Answer
$$\dfrac{8}{\sqrt{7}}-3=\dfrac{8\sqrt{7}-21}{7}$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}\frac{8}{\sqrt{7}}-3& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{8\sqrt{7}}{7}-3 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}\frac{8\sqrt{7}-21}{7}\end{aligned} $$ | |
| ① | Multiply in a numerator. $$ \color{blue}{ 8 } \cdot \sqrt{7} = 8 \sqrt{7} $$ Simplify denominator. $$ \color{blue}{ \sqrt{7} } \cdot \sqrt{7} = 7 $$ |
| ② | $$ \frac{8\sqrt{7}}{7}-3
= \frac{8\sqrt{7}}{7} \cdot \color{blue}{\frac{ 1 }{ 1}} - 3 \cdot \color{blue}{\frac{ 7 }{ 7}}
= \frac{8\sqrt{7}-21}{7} $$ |
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