Question
Answer
$$6\cdot\dfrac{\sqrt{45}}{45}=\dfrac{2\sqrt{5}}{5}$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}6 \cdot \frac{\sqrt{45}}{45}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}6 \cdot \frac{\sqrt{5}}{15} \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}\frac{6\sqrt{5}}{15} \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle3}{\textcircled {3}} } }}}\frac{ 6 \sqrt{ 5 } : \color{blue}{ 3 } } { 15 : \color{blue}{ 3 }} \xlongequal{ } \\[1 em] & \xlongequal{ }\frac{2\sqrt{5}}{5}\end{aligned} $$ | |
| ① | Divide both numerator and denominator by 3. |
| ② | $$ \color{blue}{ 6 } \cdot \sqrt{5} = 6 \sqrt{5} $$$$ \color{blue}{ 1 } \cdot 15 = 15 $$ |
| ③ | Divide numerator and denominator by $ \color{blue}{ 3 } $. |
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Simplify Radical Expression