| $$ \begin{aligned}6\sqrt{2}(3\sqrt{2}-5)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}36-30\sqrt{2}\end{aligned} $$ | |
| ① | $$ \color{blue}{ 6 \sqrt{2} } \cdot \left( 3 \sqrt{2}-5\right) = \color{blue}{ 6 \sqrt{2}} \cdot 3 \sqrt{2}+\color{blue}{ 6 \sqrt{2}} \cdot-5 = \\ = 36- 30 \sqrt{2} $$ |