Question
Answer
$$6+\dfrac{\sqrt{9}}{2}\cdot3=\dfrac{21}{2}$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}6+\frac{\sqrt{9}}{2}\cdot3& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}6+\frac{3}{2}\cdot3 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}\frac{21}{2}\end{aligned} $$ | |
| ① | $$ \sqrt{9} = 3 $$ |
| ② | Combine like terms |
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