Question
Answer
$$4\cdot\dfrac{\sqrt{8}}{2\sqrt{9}}=\dfrac{4\sqrt{2}}{3}$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}4 \cdot \frac{\sqrt{8}}{2\sqrt{9}}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}4 \cdot \frac{6\sqrt{2}}{18} \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}4 \cdot \frac{\sqrt{2}}{3} \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle3}{\textcircled {3}} } }}}\frac{4\sqrt{2}}{3}\end{aligned} $$ | |
| ① | Multiply in a numerator. $$ \color{blue}{ \sqrt{8} } \cdot \sqrt{9} = 6 \sqrt{2} $$ Simplify denominator. $$ \color{blue}{ 2 \sqrt{9} } \cdot \sqrt{9} = 18 $$ |
| ② | Divide both numerator and denominator by 6. |
| ③ | $$ \color{blue}{ 4 } \cdot \sqrt{2} = 4 \sqrt{2} $$$$ \color{blue}{ 1 } \cdot 3 = 3 $$ |
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