Question
Answer
$$4\sqrt{3}+8\sqrt{12}-\sqrt{27}=17\sqrt{3}$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}4\sqrt{3}+8\sqrt{12}-\sqrt{27}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}4\sqrt{3}+16\sqrt{3}-3\sqrt{3} \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle3}{\textcircled {3}} } }}}17\sqrt{3}\end{aligned} $$ | |
| ① | $$ 8 \sqrt{12} =
8 \sqrt{ 2 ^2 \cdot 3 } =
8 \sqrt{ 2 ^2 } \, \sqrt{ 3 } =
8 \cdot 2 \sqrt{ 3 } =
16 \sqrt{ 3 } $$ |
| ② | $$ - \sqrt{27} =
- \sqrt{ 3 ^2 \cdot 3 } =
- \sqrt{ 3 ^2 } \, \sqrt{ 3 } =
- 3 \sqrt{ 3 }$$ |
| ③ | Combine like terms |
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