Question
Answer
$$4\sqrt{27}+6\sqrt{75}=42\sqrt{3}$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}4\sqrt{27}+6\sqrt{75}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}12\sqrt{3}+30\sqrt{3} \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle3}{\textcircled {3}} } }}}42\sqrt{3}\end{aligned} $$ | |
| ① | $$ 4 \sqrt{27} =
4 \sqrt{ 3 ^2 \cdot 3 } =
4 \sqrt{ 3 ^2 } \, \sqrt{ 3 } =
4 \cdot 3 \sqrt{ 3 } =
12 \sqrt{ 3 } $$ |
| ② | $$ 6 \sqrt{75} =
6 \sqrt{ 5 ^2 \cdot 3 } =
6 \sqrt{ 5 ^2 } \, \sqrt{ 3 } =
6 \cdot 5 \sqrt{ 3 } =
30 \sqrt{ 3 } $$ |
| ③ | Combine like terms |
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