Question
Answer
$$4\sqrt{21}\cdot9\sqrt{6}=108\sqrt{14}$$
Explanation
| $$ \begin{aligned}4\sqrt{21}\cdot9\sqrt{6}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}108\sqrt{14}\end{aligned} $$ | |
| ① | $$ 36 \sqrt{126} =
36 \sqrt{ 3 ^2 \cdot 14 } =
36 \sqrt{ 3 ^2 } \, \sqrt{ 14 } =
36 \cdot 3 \sqrt{ 14 } =
108 \sqrt{ 14 } $$ |
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