Question
Answer
$$4\sqrt{2}\cdot(2+2\sqrt{3})=8\sqrt{2}+8\sqrt{6}$$
Explanation
| $$ \begin{aligned}4\sqrt{2}\cdot(2+2\sqrt{3})& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}8\sqrt{2}+8\sqrt{6}\end{aligned} $$ | |
| ① | $$ \color{blue}{ 4 \sqrt{2} } \cdot \left( 2 + 2 \sqrt{3}\right) = \color{blue}{ 4 \sqrt{2}} \cdot2+\color{blue}{ 4 \sqrt{2}} \cdot 2 \sqrt{3} = \\ = 8 \sqrt{2} + 8 \sqrt{6} $$ |
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Simplify Radical Expression