| $$ \begin{aligned}4\sqrt{10}\cdot3\sqrt{6}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}24\sqrt{15}\end{aligned} $$ | |
| ① | $$ 12 \sqrt{60} =
12 \sqrt{ 2 ^2 \cdot 15 } =
12 \sqrt{ 2 ^2 } \, \sqrt{ 15 } =
12 \cdot 2 \sqrt{ 15 } =
24 \sqrt{ 15 } $$ |