Question
Answer
$$\dfrac{4}{\sqrt{2}}+\dfrac{2}{\sqrt{3}}=\dfrac{12\sqrt{2}+4\sqrt{3}}{6}$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}\frac{4}{\sqrt{2}}+\frac{2}{\sqrt{3}}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{4\sqrt{2}}{2}+\frac{2\sqrt{3}}{3} \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}\frac{12\sqrt{2}+4\sqrt{3}}{6}\end{aligned} $$ | |
| ① | Multiply in a numerator. $$ \color{blue}{ 4 } \cdot \sqrt{2} = 4 \sqrt{2} $$ Simplify denominator. $$ \color{blue}{ \sqrt{2} } \cdot \sqrt{2} = 2 $$Multiply in a numerator. $$ \color{blue}{ 2 } \cdot \sqrt{3} = 2 \sqrt{3} $$ Simplify denominator. $$ \color{blue}{ \sqrt{3} } \cdot \sqrt{3} = 3 $$ |
| ② | $$ \frac{4\sqrt{2}}{2}+\frac{2\sqrt{3}}{3}
= \frac{4\sqrt{2}}{2} \cdot \color{blue}{\frac{ 3 }{ 3}} + \frac{2\sqrt{3}}{3} \cdot \color{blue}{\frac{ 2 }{ 2}}
= \frac{12\sqrt{2}+4\sqrt{3}}{6} $$ |
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