Question
Answer
$$3\sqrt{98}-6\sqrt{50}=-9\sqrt{2}$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}3\sqrt{98}-6\sqrt{50}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}21\sqrt{2}-30\sqrt{2} \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle3}{\textcircled {3}} } }}}-9\sqrt{2}\end{aligned} $$ | |
| ① | $$ 3 \sqrt{98} =
3 \sqrt{ 7 ^2 \cdot 2 } =
3 \sqrt{ 7 ^2 } \, \sqrt{ 2 } =
3 \cdot 7 \sqrt{ 2 } =
21 \sqrt{ 2 } $$ |
| ② | $$ - 6 \sqrt{50} =
-6 \sqrt{ 5 ^2 \cdot 2 } =
-6 \sqrt{ 5 ^2 } \, \sqrt{ 2 } =
-6 \cdot 5 \sqrt{ 2 } =
-30 \sqrt{ 2 } $$ |
| ③ | Combine like terms |
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