Question
Answer
$$3\sqrt{3}(\sqrt{27}-2\sqrt{2})=27-6\sqrt{6}$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}3\sqrt{3}(\sqrt{27}-2\sqrt{2})& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}3\sqrt{3}(3\sqrt{3}-2\sqrt{2}) \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}27-6\sqrt{6}\end{aligned} $$ | |
| ① | $$ \sqrt{27} =
\sqrt{ 3 ^2 \cdot 3 } =
\sqrt{ 3 ^2 } \, \sqrt{ 3 } =
3 \sqrt{ 3 }$$ |
| ② | $$ \color{blue}{ 3 \sqrt{3} } \cdot \left( 3 \sqrt{3}- 2 \sqrt{2}\right) = \color{blue}{ 3 \sqrt{3}} \cdot 3 \sqrt{3}+\color{blue}{ 3 \sqrt{3}} \cdot- 2 \sqrt{2} = \\ = 27- 6 \sqrt{6} $$ |
This page was created using
Simplify Radical Expression