Question
Answer
$$\dfrac{3}{\sqrt{2}}+\sqrt{5}=\dfrac{3\sqrt{2}+2\sqrt{5}}{2}$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}\frac{3}{\sqrt{2}}+\sqrt{5}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{3\sqrt{2}}{2}+\sqrt{5} \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}\frac{3\sqrt{2}+2\sqrt{5}}{2}\end{aligned} $$ | |
| ① | Multiply in a numerator. $$ \color{blue}{ 3 } \cdot \sqrt{2} = 3 \sqrt{2} $$ Simplify denominator. $$ \color{blue}{ \sqrt{2} } \cdot \sqrt{2} = 2 $$ |
| ② | $$ \frac{3\sqrt{2}}{2}+\sqrt{5}
= \frac{3\sqrt{2}}{2} \cdot \color{blue}{\frac{ 1 }{ 1}} + \sqrt{5} \cdot \color{blue}{\frac{ 2 }{ 2}}
= \frac{3\sqrt{2}+2\sqrt{5}}{2} $$ |
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