Question
Answer
$$2\cdot\dfrac{\sqrt{3}}{5}-\sqrt{3}=\dfrac{-3\sqrt{3}}{5}$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}2 \cdot \frac{\sqrt{3}}{5}-\sqrt{3}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{2\sqrt{3}-5\sqrt{3}}{5} \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}\frac{-3\sqrt{3}}{5}\end{aligned} $$ | |
| ① | $$ 2 \cdot \frac{\sqrt{3}}{5}-\sqrt{3}
= \frac{2\sqrt{3}}{5} \cdot \color{blue}{\frac{ 1 }{ 1}} - \sqrt{3} \cdot \color{blue}{\frac{ 5 }{ 5}}
= \frac{2\sqrt{3}-5\sqrt{3}}{5} $$ |
| ② | Simplify numerator and denominator |
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