Question
Answer
$$2\cdot\dfrac{\sqrt{3}}{4}\sqrt{27}=\dfrac{9}{2}$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}2 \cdot \frac{\sqrt{3}}{4}\sqrt{27}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}2 \cdot \frac{\sqrt{3}}{4}\cdot3\sqrt{3} \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}\frac{18}{4} \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle3}{\textcircled {3}} } }}} \frac{ 18 : \color{orangered}{ 2 } }{ 4 : \color{orangered}{ 2 }} \xlongequal{ } \\[1 em] & \xlongequal{ }\frac{9}{2}\end{aligned} $$ | |
| ① | $$ \sqrt{27} =
\sqrt{ 3 ^2 \cdot 3 } =
\sqrt{ 3 ^2 } \, \sqrt{ 3 } =
3 \sqrt{ 3 }$$ |
| ② | $$ \color{blue}{ 2 \sqrt{3} } \cdot 3 \sqrt{3} = 18 $$$$ \color{blue}{ 4 } \cdot 1 = 4 $$ |
| ③ | Divide both the top and bottom numbers by $ \color{orangered}{ 2 } $. |
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