Question
Answer
$$2\cdot\dfrac{\sqrt{2}}{\sqrt{2}}-\dfrac{1}{\sqrt{2}}=\dfrac{4-\sqrt{2}}{2}$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}2 \cdot \frac{\sqrt{2}}{\sqrt{2}}-\frac{1}{\sqrt{2}}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}2\cdot\frac{2}{2}-\frac{\sqrt{2}}{2} \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}\frac{4-\sqrt{2}}{2}\end{aligned} $$ | |
| ① | Multiply in a numerator. $$ \color{blue}{ \sqrt{2} } \cdot \sqrt{2} = 2 $$ Simplify denominator. $$ \color{blue}{ \sqrt{2} } \cdot \sqrt{2} = 2 $$Multiply in a numerator. $$ \color{blue}{ 1 } \cdot \sqrt{2} = \sqrt{2} $$ Simplify denominator. $$ \color{blue}{ \sqrt{2} } \cdot \sqrt{2} = 2 $$ |
| ② | $$ 2\cdot\frac{2}{2}-\frac{\sqrt{2}}{2}
= 2 \cdot \color{blue}{\frac{ 2 }{ 2}} - \frac{\sqrt{2}}{2} \cdot \color{blue}{\frac{ 1 }{ 1}}
= \frac{4-\sqrt{2}}{2} $$ |
This page was created using
Simplify Radical Expression