Question
Answer
$$2\cdot\dfrac{\sqrt{15}}{\sqrt{27}}=\dfrac{2\sqrt{5}}{3}$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}2 \cdot \frac{\sqrt{15}}{\sqrt{27}}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}2 \cdot \frac{9\sqrt{5}}{27} \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}2 \cdot \frac{\sqrt{5}}{3} \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle3}{\textcircled {3}} } }}}\frac{2\sqrt{5}}{3}\end{aligned} $$ | |
| ① | Multiply in a numerator. $$ \color{blue}{ \sqrt{15} } \cdot \sqrt{27} = 9 \sqrt{5} $$ Simplify denominator. $$ \color{blue}{ \sqrt{27} } \cdot \sqrt{27} = 27 $$ |
| ② | Divide both numerator and denominator by 9. |
| ③ | $$ \color{blue}{ 2 } \cdot \sqrt{5} = 2 \sqrt{5} $$$$ \color{blue}{ 1 } \cdot 3 = 3 $$ |
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