Question
Answer
$$2\sqrt{14}\cdot(7-5\sqrt{21})=14\sqrt{14}-70\sqrt{6}$$
Explanation
| $$ \begin{aligned}2\sqrt{14}\cdot(7-5\sqrt{21})& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}14\sqrt{14}-70\sqrt{6}\end{aligned} $$ | |
| ① | $$ \color{blue}{ 2 \sqrt{14} } \cdot \left( 7- 5 \sqrt{21}\right) = \color{blue}{ 2 \sqrt{14}} \cdot7+\color{blue}{ 2 \sqrt{14}} \cdot- 5 \sqrt{21} = \\ = 14 \sqrt{14}- 70 \sqrt{6} $$ |
This page was created using
Simplify Radical Expression