Question
Answer
$$\dfrac{10}{\sqrt{35}}-5=\dfrac{2\sqrt{35}-35}{7}$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}\frac{10}{\sqrt{35}}-5& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{10\sqrt{35}}{35}-5 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}\frac{10\sqrt{35}-175}{35} \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle3}{\textcircled {3}} } }}}\frac{2\sqrt{35}-35}{7}\end{aligned} $$ | |
| ① | Multiply in a numerator. $$ \color{blue}{ 10 } \cdot \sqrt{35} = 10 \sqrt{35} $$ Simplify denominator. $$ \color{blue}{ \sqrt{35} } \cdot \sqrt{35} = 35 $$ |
| ② | $$ \frac{10\sqrt{35}}{35}-5
= \frac{10\sqrt{35}}{35} \cdot \color{blue}{\frac{ 1 }{ 1}} - 5 \cdot \color{blue}{\frac{ 35 }{ 35}}
= \frac{10\sqrt{35}-175}{35} $$ |
| ③ | Divide both numerator and denominator by 5. |
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