Question
Answer
$$\dfrac{1}{3}-3\dfrac{\sqrt{27}}{9}=\dfrac{1-3\sqrt{3}}{3}$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}\frac{1}{3}-3\frac{\sqrt{27}}{9}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{1}{3}-3\frac{\sqrt{3}}{3} \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}\frac{1-3\sqrt{3}}{3}\end{aligned} $$ | |
| ① | Divide both numerator and denominator by 3. |
| ② | $$ \frac{1}{3}-3\frac{\sqrt{3}}{3}
= \frac{1}{3} \cdot \color{blue}{\frac{ 3 }{ 3}} - \frac{3\sqrt{3}}{3} \cdot \color{blue}{\frac{ 1 }{ 1}}
= \frac{1-3\sqrt{3}}{3} $$ |
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