Question
Answer
$$-\sqrt{42}\cdot4\sqrt{7}=-28\sqrt{6}$$
Explanation
| $$ \begin{aligned}-\sqrt{42}\cdot4\sqrt{7}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}-28\sqrt{6}\end{aligned} $$ | |
| ① | $$ - 4 \sqrt{294} =
-4 \sqrt{ 7 ^2 \cdot 6 } =
-4 \sqrt{ 7 ^2 } \, \sqrt{ 6 } =
-4 \cdot 7 \sqrt{ 6 } =
-28 \sqrt{ 6 } $$ |
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