Question
Answer
$$-\sqrt{27}-3\sqrt{6}+2\sqrt{3}=-\sqrt{3}-3\sqrt{6}$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}-\sqrt{27}-3\sqrt{6}+2\sqrt{3}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}-3\sqrt{3}-3\sqrt{6}+2\sqrt{3} \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}-\sqrt{3}-3\sqrt{6}\end{aligned} $$ | |
| ① | $$ - \sqrt{27} =
- \sqrt{ 3 ^2 \cdot 3 } =
- \sqrt{ 3 ^2 } \, \sqrt{ 3 } =
- 3 \sqrt{ 3 }$$ |
| ② | Combine like terms |
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