Question
Answer
$$-7+\sqrt{7}^2-4\cdot6\cdot\dfrac{-5}{12}=0$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}-7+\sqrt{7}^2-4\cdot6\cdot\frac{-5}{12}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}-7+\sqrt{7}^2-\frac{-120}{12} \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}-7+7-\frac{-120}{12} \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle3}{\textcircled {3}} } }}}0-\frac{-120}{12} \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle4}{\textcircled {4}} } }}}\frac{0}{12} \xlongequal{ } \\[1 em] & \xlongequal{ }0\end{aligned} $$ | |
| ① | $$ \color{blue}{ 24 } \cdot -5 = -120 $$$$ \color{blue}{ 1 } \cdot 12 = 12 $$ |
| ② | $$ \sqrt{7}^2 =
\sqrt{7} ^2 =
\lvert 7 \rvert =
7 $$ |
| ③ | Combine like terms |
| ④ | $$ 0-\frac{-120}{12}
= 0 \cdot \color{blue}{\frac{ 12 }{ 12}} - \frac{-120}{12} \cdot \color{blue}{\frac{ 1 }{ 1}}
= \frac{0}{12} $$ |
This page was created using
Simplify Radical Expression