Question
Answer
$$-6\sqrt{48}=-24\sqrt{3}$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}-6\sqrt{48}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}-6\cdot \sqrt{ 16 \cdot 3 } \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}-6\cdot \sqrt{ 16 } \cdot \sqrt{ 3 } \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle3}{\textcircled {3}} } }}}-6\cdot4 \sqrt{ 3 } \xlongequal{ } \\[1 em] & \xlongequal{ }-24\sqrt{3}\end{aligned} $$ | |
| ① | Factor out the largest perfect square of 48. ( in this example we factored out $ 16 $ ) |
| ② | Rewrite $ \sqrt{ 16 \cdot 3 } $ as the product of two radicals. |
| ③ | The square root of $ 16 $ is $ 4 $. |
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