Question
Answer
$$-4\sqrt{3}-\sqrt{49}-6\sqrt{27}=-22\sqrt{3}-7$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}-4\sqrt{3}-\sqrt{49}-6\sqrt{27}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}-4\sqrt{3}-7-18\sqrt{3} \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle3}{\textcircled {3}} } }}}-22\sqrt{3}-7\end{aligned} $$ | |
| ① | $$ - \sqrt{49} = -1 \cdot 7 = -7 $$ |
| ② | $$ - 6 \sqrt{27} =
-6 \sqrt{ 3 ^2 \cdot 3 } =
-6 \sqrt{ 3 ^2 } \, \sqrt{ 3 } =
-6 \cdot 3 \sqrt{ 3 } =
-18 \sqrt{ 3 } $$ |
| ③ | Combine like terms |
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